honours - My honours project from 2012.

Age	Commit message (Collapse)	Author
2012-11-09	Add an MCF operator to the separate solver	Carlo Zancanaro
	For the solver utility it'd be good to have MCF problems, so here they are! Format is: MCF<supplies, arcs>(cost*) Supplies is a [int,int,int,...], where each int represents a new node Arcs is [int:int, int:int, int:int, ...] where each int:int pair represents an edge from the first to the second (1 indexed from the "supplies" array). Costs is the argument to the function. There must be as many costs as arcs, and they are set from left to right, in order.